2015 Istanbul Open – Doubles

From Wikipedia, the free encyclopedia
Doubles
2015 Istanbul Open
Final
ChampionsMoldova Radu Albot
Serbia Dušan Lajović
Runners-upSweden Robert Lindstedt
Austria Jürgen Melzer
Score6–4, 7–6(7–2)
Events
Singles Doubles
Istanbul Open · 2016 →

This is the first edition of the tournament.
Radu Albot and Dušan Lajović won the title, defeating Robert Lindstedt and Jürgen Melzer in the final, 6–4, 7–6(7–2).

Seeds[edit]

Draw[edit]

Key[edit]

Draw[edit]

First round Quarterfinals Semifinals Final
1 Sweden R Lindstedt
Austria J Melzer
6 6
Alt Russia F Chervyakov
Zimbabwe M Fynn
2 2 1 Sweden R Lindstedt
Austria J Melzer
6 7
France F Martin
India P Raja
2 3 Belarus A Bury
Russia T Gabashvili
1 5
Belarus A Bury
Russia T Gabashvili
6 6 1 Sweden R Lindstedt
Austria J Melzer
6 6
4 Croatia M Pavić
New Zealand M Venus
6 6 New Zealand M Daniell
Colombia S Giraldo
2 1
Belarus S Betov
Russia A Kuznetsov
3 4 4 Croatia M Pavić
New Zealand M Venus
2 4
Slovenia B Kavčič
Argentina D Schwartzman
7 2 [3] New Zealand M Daniell
Colombia S Giraldo
6 6
New Zealand M Daniell
Colombia S Giraldo
5 6 [10] 1 Sweden R Lindstedt
Austria J Melzer
4 62
Kazakhstan A Golubev
Uzbekistan D Istomin
6 6 Moldova R Albot
Serbia D Lajović
6 77
Kazakhstan M Kukushkin
Kazakhstan A Nedovyesov
3 4 Kazakhstan A Golubev
Uzbekistan D Istomin
3 3
WC Turkey T Altuna
Georgia (country) N Basilashvili
3 2 3 Australia C Guccione
Brazil A Sá
6 6
3 Australia C Guccione
Brazil A Sá
6 6 3 Australia C Guccione
Brazil A Sá
4 65
  Moldova R Albot
Serbia D Lajović
6 6 Moldova R Albot
Serbia D Lajović
6 77
WC Turkey M İlhan
Turkey C İlkel
3 3 Moldova R Albot
Serbia D Lajović
69 6 [10]
Sweden J Brunström
Israel J Erlich
5 5 2 Austria O Marach
Austria P Oswald
711 2 [8]
2 Austria O Marach
Austria P Oswald
7 7

References[edit]