File talk:Blocking oscillator.jpg

I wonder where the base current for initial bias comes from. Are we relying on the capacitor having a high or slight amount of internal leakage. If I made up this circuit with a good capacitor..... would it work? Please comment somebody. --Technut 08:28, 28 September 2006 (UTC)[reply]

It's better:

90.191.190.76 (talk) 21:22, 2 December 2008 (UTC)[reply]

Here is what I have Been able to do in the past that seems to help, in Parallel with the Capacitor, I use a resistor or a Variable Resistor, this will help to create an amount of leak back to the Base. I think someone should Correct the Schematic to reflect this because it is important. — Preceding unsigned comment added by 108.246.55.196 (talk) 15:11, 26 January 2013 (UTC)[reply]