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Acefylline clofibrol

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(Redirected from C19H21ClN4O5)
Acefylline clofibrol
Clinical data
Routes of
administration
Intramuscular, Intravenous
Identifiers
  • 2-(4-Chlorophenoxy)-2-methylpropyl (1,3-dimethyl-2,6-dioxo-1,2,3,6-tetrahydro-7H-purin-7-yl)acetate
CAS Number
PubChem CID
ChemSpider
UNII
ChEMBL
CompTox Dashboard (EPA)
Chemical and physical data
FormulaC19H21ClN4O5
Molar mass420.85 g·mol−1
3D model (JSmol)
  • Clc3ccc(OC(C)(C)COC(=O)Cn1c2c(nc1)N(C(=O)N(C2=O)C)C)cc3
  • InChI=1S/C19H21ClN4O5/c1-19(2,29-13-7-5-12(20)6-8-13)10-28-14(25)9-24-11-21-16-15(24)17(26)23(4)18(27)22(16)3/h5-8,11H,9-10H2,1-4H3 checkY
  • Key:ICVMNUSJJHSLLM-UHFFFAOYSA-N checkY
 ☒NcheckY (what is this?)  (verify)

Acefylline clofibrol is a derivative of acefylline and clofibrate used as a hypolipidemic agent.[1][2]

References

[edit]
  1. ^ FR 2393803, Tamietto, Teresio; Franzone, Jose Sebastian, "2-(p-Chlorophenoxy)-2-methylpropyl theophylline-7-acetate useful as a hypocholesterolemiant", published 1979 
  2. ^ euroasiarnd Archived August 15, 2011, at the Wayback Machine