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Alfred Huber (tennis)

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(Redirected from Fredl Huber)

Alfred Huber
Alfred Huber in 1957
Country (sports) Austria
Born(1930-05-15)15 May 1930
Vienna, Austria
Died25 May 1972(1972-05-25) (aged 42)
Singles
Grand Slam singles results
Wimbledon3R (1950, 1952, 1955)
Doubles
Grand Slam doubles results
WimbledonQF (1953)
Grand Slam mixed doubles results
Wimbledon4R (1952, 1953)

Alfred "Freddie" Huber (15 May 1930 – 25 May 1972) was an Austrian tennis and ice hockey player. He began his tennis career in 1946. He won the British Covered Court Championships in 1956. He competed at Wimbledon in 1949–57, but never advanced through the third round.[1] He competed in the hockey tournament at the 1948 Winter Olympics.[2]

References

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  1. ^ "Alfred (Freddie) Huber". tennisarchives.com. Retrieved 5 January 2015.
  2. ^ Evans, Hilary; Gjerde, Arild; Heijmans, Jeroen; Mallon, Bill; et al. "Fredl Huber Olympic Results". Olympics at Sports-Reference.com. Sports Reference LLC. Archived from the original on 17 April 2020. Retrieved 12 May 2019.
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