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Yeylaq Marshun

Coordinates: 36°18′11″N 49°23′34″E / 36.30306°N 49.39278°E / 36.30306; 49.39278
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(Redirected from Margun, Zanjan)
Yeylaq Marshun
ييلاق مرشون
village
Yeylaq Marshun is located in Iran
Yeylaq Marshun
Yeylaq Marshun
Coordinates: 36°18′11″N 49°23′34″E / 36.30306°N 49.39278°E / 36.30306; 49.39278
Country Iran
ProvinceZanjan
CountyAbhar
BakhshCentral
Rural DistrictHowmeh
Population
 (2006)
 • Total432
Time zoneUTC+3:30 (IRST)
 • Summer (DST)UTC+4:30 (IRDT)

Yeylaq Marshun (Persian: ييلاق مرشون, also Romanized as Yeylāq Marshūn; also known as Marchīn, Marchon, Marchūn, Margun, and Marshūn)[1] is a village in Howmeh Rural District, in the Central District of Abhar County, Zanjan Province, Iran. At the 2006 census, its population was 432, in 77 families.[2]

References

[edit]
  1. ^ Yeylaq Marshun can be found at GEOnet Names Server, at this link, by opening the Advanced Search box, entering "-3074178" in the "Unique Feature Id" form, and clicking on "Search Database".
  2. ^ "Census of the Islamic Republic of Iran, 1385 (2006)" (Excel). Statistical Center of Iran. Archived from the original on 2011-09-20.