1988 United States presidential election in the District of Columbia

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1988 United States presidential election in the District of Columbia

← 1984 November 8, 1988 1992 →
 
Nominee Michael Dukakis George H. W. Bush
Party Democratic Republican
Home state Massachusetts Texas
Running mate Lloyd Bentsen Dan Quayle
Electoral vote 3 0
Popular vote 159,407 27,590
Percentage 82.65% 14.30%

Ward Results
Dukakis
  60-70%
  70-80%
  80-90%
  90-100%


President before election

Ronald Reagan
Republican

Elected President

George H. W. Bush
Republican

The 1988 United States presidential election in the District of Columbia took place on November 8, 1988, as part of the 1988 United States presidential election. Voters chose three representatives, or electors, to the Electoral College, who voted for president and vice president.

Washington, D.C. overwhelmingly voted for Governor Michael Dukakis of Massachusetts, the Democratic candidate. Vice President George H. W. Bush received 14.3% of the vote. This is the most recent election in which the Republican candidate received more than 10% of the vote in the District of Columbia, and it was one of only two areas that leaned more Republican than in the presidential election of 1984, which had resulted in a Republican landslide, the other being Tennessee.

Results[edit]

1988 United States presidential election in the District of Columbia[1]
Party Candidate Votes Percentage Electoral votes
Democratic Michael Dukakis 159,407 82.65% 3
Republican George H. W. Bush 27,590 14.30% 0
New Alliance Lenora Fulani 2,901 1.50% 0
Libertarian Ron Paul 554 0.29% 0

See also[edit]

References[edit]

  1. ^ "1988 Presidential General Election Results - District of Columbia". US Election Atlas.