1845 Mississippi gubernatorial election
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The 1845 Mississippi gubernatorial election was held on November 3, 1845, to elect the governor of Mississippi. Albert G. Brown, a Democrat won against Whig Thomas Coopwood and candidate Issac N. Davis.[1][2]
Results[edit]
| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Democratic | Albert G. Brown | 28,310 | 66.1% | |
| Whig | Thomas B. Coopwood | 12,852 | 30.0% | |
| Issac N. Davis | 1,683 | 3.9% | ||
| Total votes | 42,854 | 100.00 | ||
| Democratic hold | ||||
| Elections in Mississippi |
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References[edit]
- ^ a b Glashan, Roy R. (1979). American Governors and Gubernatorial Elections, 1775-1978. Westport, CT: Meckler Books. pp. 168–169.
- ^ Rowland, Dunbar (1925). History of Mississippi, the Heart of the South. Vol. 1. S. J. Clarke publishing Company.
- ^ Dublin, Michael J. (2011). United States Gubernatorial Elections, 1776-1860 : The Official Results by State and County. McFarland & Company, Incorporated Publishers. p. 132. ISBN 9780786453245.
- ^ "The Results for Governor" (fee required). The Mississippi Trader and Natchez Gazette. January 17, 1846. p. 2.