1956 World Table Tennis Championships – Women's singles

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1956 Women's singles
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Main article: 1956 World Table Tennis Championships

The 1956 World Table Tennis Championships women's singles was the 23rd edition of the women's singles championship.[1][2] Tomi Okawa defeated Kiiko Watanabe in the final by three sets to two, to win the title.[3]

Results[edit]

Round of 16 Quarterfinals Semifinals Final
Japan Tomi Okawa 21 21 20 21
Japan Kiyoko Tasaka 14 10 22 13 Japan Okawa 21 21 21
South Korea Wie Sang Sook 21 21 21 South Korea Wie Sang Sook 16 17 10
Japan Chizuko Suda 16 13 6 Japan Okawa 21 16 21 17 21
England Ann Haydon 21 21 21 Japan Eguchi 17 21 15 21 13
Japan Kikuko Yamakawa 7 6 6 Japan Eguchi 21 22 21
Japan Fujie Eguchi 21 21 21 England Haydon 13 20 16
Japan Chicko Ikuno 18 16 8 Japan Okawa 21 13 23 9 21
Romania Ella Zeller 18 21 21 21 Japan Watanabe 15 21 21 21 16
Japan Shizuyo Narahara 21 13 16 13 Romania Zeller 21 21 21
England Diane Rowe 21 21 23 England Rowe D 8 8 17
Japan Taeko Namba 12 9 21 Romania Zeller 21 21 21 16 15
Hong Kong Baguio Wong 21 21 21 Japan Watanabe 16 14 23 21 21
Japan Hideko Nakayama 15 14 9 Hong Kong Baguio Wong 12 21 22 21 19
China Chiu Chung-Hui 14 22 23 13 Japan Watanabe 21 17 24 12 21
Japan Kiiko Watanabe 21 20 25 21

See also[edit]

List of World Table Tennis Championships medalists

References[edit]

  1. ^ "List of Winners". All About Tennis.
  2. ^ "1956 results" (PDF). International Table Tennis Federation. Archived from the original (PDF) on 2012-04-12.
  3. ^ Montague, Trevor (2004). A-Z of Sport, pages 699-700. The Bath Press. ISBN 0-316-72645-1.
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