2021 Cleveland Open – Doubles

Treat Huey and Nathaniel Lammons were the defending champions^[1] but only Huey chose to defend his title, partnering Sem Verbeek. Huey lost in the quarterfinals to Emilio Gómez and Roberto Quiroz.

Robert Galloway and Alex Lawson won the title after defeating Evan King and Hunter Reese 7–5, 6–7^(5–7), [11–9] in the final.

Seeds[edit]

First round					Quarterfinals					Semifinals				Final

1	T Huey S Verbeek	5	6	[12]
	JC Aragone R Cid Subervi	7	1	[10]	1	T Huey S Verbeek	5	6	[7]
	T-S Kwiatkowski A Ritschard	5	6	[11]		E Gómez R Quiroz	7	2	[10]
	E Gómez R Quiroz	7	2	[13]							E Gómez R Quiroz	1	6³
3	E King H Reese	4	6	[10]						3	E King H Reese	6	7⁷
	A Gómez JA Ore	6	3	[8]	3	E King H Reese	6	7¹⁰
	M Krueger Ma Redlicki	4	6	[10]		M Krueger Ma Redlicki	0	6⁸
	D King Mi Redlicki	6	2	[5]										3	E King H Reese	5	7⁷	[9]
	N Barrientos R Gonzales	6	6											2	R Galloway A Lawson	7	6⁵	[11]
WC	Matthew Chen Jonathan Powell	2	4			N Barrientos R Gonzales	6	6
	H Johnson Y Johnson	6	6			H Johnson Y Johnson	4	3
4	D Novikov A Pavić	3	2								N Barrientos R Gonzales	5	4
WC	Felix Corwin James Hopper	w/o								2	R Galloway A Lawson	7	6
WC	Z Svajda M Torpegaard				WC	F Corwin J Hopper	7	4	[5]
	N Chappell M Pervolarakis	3	1		2	R Galloway A Lawson	5	6	[10]
2	R Galloway A Lawson	6	6