2023 Chennai Open Challenger – Doubles

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Doubles
2023 Chennai Open Challenger
Final
ChampionsUnited Kingdom Jay Clarke
India Arjun Kadhe
Runners-upAustria Sebastian Ofner
Croatia Nino Serdarušić
Score6–0, 6–4
Events
Singles Doubles
← 2019 · Chennai Open Challenger · 2024 →

Gianluca Mager and Andrea Pellegrino were the defending champions[1] but chose not to defend their title.

Jay Clarke and Arjun Kadhe won the title after defeating Sebastian Ofner and Nino Serdarušić 6–0, 6–4 in the final.

Seeds[edit]

Draw[edit]

Key[edit]

First round Quarterfinals Semifinals Final
1 India S Balaji
India J Nedunchezhiyan
6 7
Portugal F Ferreira Silva
United States N Moreno de Alboran
4 5 1 India S Balaji
India J Nedunchezhiyan
77 6
Chinese Taipei Y-h Hsu
Indonesia C Rungkat
612 1r WC India S Nagal
India M Sasikumar
65 0
WC India S Nagal
India M Sasikumar
714 2 1 India S Balaji
India J Nedunchezhiyan
6 65 [4]
4 India A Chandrasekar
India VS Prashanth
79 1 [7] Austria S Ofner
Croatia N Serdarušić
4 77 [10]
United Kingdom R Peniston
Czech Republic D Svrčina
67 6 [10] United Kingdom R Peniston
Czech Republic D Svrčina
1 77 [4]
Bulgaria D Kuzmanov
Serbia H Međedović
5 4 Austria S Ofner
Croatia N Serdarušić
6 63 [10]
Austria S Ofner
Croatia N Serdarušić
7 6 Austria S Ofner
Croatia N Serdarušić
0 4
Alt Australia D Kelly
Australia D Sweeny
6 3 [7] United Kingdom J Clarke
India A Kadhe
6 6
United Kingdom J Clarke
India A Kadhe
3 6 [10] United Kingdom J Clarke
India A Kadhe
1 710 [10]
WC India R Ramanathan
India V Vardhan
6 64 [5] 3 South Korea J-s Nam
South Korea M-k Song
6 68 [8]
3 South Korea J-s Nam
South Korea M-k Song
1 77 [10] United Kingdom J Clarke
India A Kadhe
7 4 [10]
Italy F Maestrelli
Italy L Nardi
6 6 Czech Republic P Nouza
Czech Republic A Paulson
5 6 [8]
Australia C Puttergill
Australia A Santillan
2 3 Italy F Maestrelli
Italy L Nardi
3 4
Czech Republic P Nouza
Czech Republic A Paulson
6 6 Czech Republic P Nouza
Czech Republic A Paulson
6 6
2 Australia M Polmans
Australia M Purcell
4 4

References[edit]

External links[edit]