De Soto, Nebraska
De Soto, Nebraska | |
|---|---|
| Coordinates: 41°30′4.15″N 96°3′24.15″W / 41.5011528°N 96.0567083°W | |
| Country | United States |
| State | Nebraska |
| County | Washington |
| Elevation | 1,007 ft (307 m) |
| Time zone | UTC-6 (Central (CST)) |
| • Summer (DST) | UTC-5 (CDT) |
| Area code | 402 |
De Soto is an unincorporated community in Washington County, Nebraska, United States.[1] It was named in honor of the sixteenth-century Spanish explorer, Hernando De Soto.[2] De Soto was founded in 1855 and served as the county seat from 1858-1866. During its heyday, the town hosted many flourishing new businesses: hotels, saloons, stores, newspapers and banks.[3]
De Soto contains farmland with about three families residing there.[4]
References[edit]
- ^ a b U.S. Geological Survey Geographic Names Information System: De Soto, Nebraska
- ^ Hernando De Soto[usurped]
- ^ "DeSoto Townsite - Washington County Historical Association". Archived from the original on October 11, 2008. Retrieved June 24, 2008.
- ^ Kancoll.org
External links[edit]
Municipalities and communities of Washington County, Nebraska, United States | ||
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