Talk:Brunt–Väisälä frequency

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Untitled[edit]

Um, in the context section, it says that it can be that N^2 < 0. I'm no expert, but since none of the previous equations invoke imaginary numbers, I'm assuming that's a typo or vandalism. Consequently, I'm removing changing the N^2 to N. --Warren Platts

We are studying linear waves and so a complex context is assumed: N^2 < 0 means the atmosphere is convectively unstable. 131.111.17.19 (talk) 20:54, 27 July 2013 (UTC)[reply]

I don't want to tread on any toes by editing the article directly, but unless I'm very much mistaken, since $\rho =\rho (z)$ , the partials ${\frac {\partial \rho (z)}{\partial z}}$ should be exact: ${\frac {d\rho }{dz}}$ . Jcwhitehead (talk) 23:10, 7 April 2014 (UTC)[reply]

I don't think that's quite right. Density rarely depends only on height.

N

emerges from studying waves in stratified fluids where the partial derivative is used.Jobla6 17:25, 26 September 2019 (UTC) — Preceding unsigned comment added by Jobla6 (talk • contribs)

Symbol origin[edit]

Does anyone know why N is used as the symbol? Ohmanger (talk) 16:26, 7 January 2016 (UTC)[reply]

Derivation Incorrect[edit]

The solution to the diferential equation

{\frac {\partial ^{2}z'}{\partial t^{2}}}={\frac {g}{\rho _{0}}}{\frac {\partial \rho (z)}{\partial z}}z'

should be : $z'=w_{1}e^{i{\sqrt {N^{2}}}t}\!+w_{2}e^{-i{\sqrt {N^{2}}}t}\!$ , since it is a second order differential equation. We need the second constant to describe the runaway growth that is described later, which could be in either direction.

Pavan7411 (talk) 17:19, 1 September 2023 (UTC)[reply]