Talk:Stokes radius

There is a sentence "since most molecules are not perfectly spherical, the Stokes radius ist smaller than the effective radius (or the rotational radius). " Does "ist" in the sentence mean is or isn't? Anyone has an idea?

Reply to previous comment[edit]

Does "ist" in the sentence mean is or isn't? Anyone has an idea?

It should be 'is' ('ist' is the German form of 'is').

There is also some inconsistency as to whether it's Stoke's or Stokes radius in this article.

-It comes from Sir George Gabriel Stokes. MVV

HL

Suggestion[edit]

It would be helpful to know what the variables stand for.137.48.19.41 14:28, 20 October 2006 (UTC)[reply]

Correct form is Stokes' radius. So it is neither Stokes radius nor Stoke's radius.

Drag force calculations[edit]

At what velocity a particle of radius 10 micrometer will move in an airstream of flow 2.75 m/s? the motion of particle is in the same direction as that of airflow. —The preceding unsigned comment was added by 202.54.42.61 (talk) 13:23, 9 February 2007 (UTC).[reply]

What is D?[edit]

"...Stokes radius is proportional to frictional coefficient f and inverse proportional to viscosity η:..." but there is no D in the following equation —Preceding unsigned comment added by Optics guy07 (talk • contribs) 03:14, 5 October 2007 (UTC)[reply]

D is the diffusion coefficient of the particle. I have added this to the article. Maartend8 (talk) 15:26, 22 March 2008 (UTC)[reply]

What is f?[edit]

Hello guys,

It says that the Stokes radius is proportional to f but there is not f at all in the equation.

Jorfoas (talk) 03:20, 5 March 2009 (UTC)[reply]

Invers proportional to the viscosity?[edit]

Is the Stokes radius really invers proportional to the viscosity? Because the diffusioncoefficient is also changing, when the viscosity is changing ( $\ D\sim {\frac {1}{\eta }}$ ), and therefor the viscosity has no effect to the stokes radius. --132.230.80.237 (talk) 10:21, 11 May 2010 (UTC)[reply]

Rewrite it to the form of D as a function of viscosity, keeping everything else constant, and it should be fairly natural that increasing the viscosity will reduce the diffusion. - 83.233.146.154 (talk) 15:22, 3 March 2012 (UTC)[reply]

Redirection[edit]

Would it be possible to redirect the search term "Hydrodynamic radius" here? I was looking for that but didn't come across this article, even though it was what I was looking for. (I found this article from surfing Wikipedia and wondering who a man called Stokes was.) — Preceding unsigned comment added by 68.149.170.235 (talk) 04:37, 8 May 2012 (UTC)[reply]

Never mind, there is a page for Hydrodynamic Radius. Sorry. — Preceding unsigned comment added by 68.149.170.235 (talk) 04:45, 8 May 2012 (UTC)[reply]