User talk:Qwerty123uiop

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Electrostatic self-energy of the object (II)[edit]

I don't know if I'm responding on the discussion I've made (if I am, please, say it to me), but here's my problem:

We have

V = kq/r (Eq. 1) , dq = rho 4πr^2 dr (Eq. 2) , and dU = Vdq (Eq. 3).

If we integrate (Eq. 3) from 0 to r (we represent this integral with integral()), we calculate the electrostatic self-energy of the object:

U = integral(Vdq) (Eq. 4)

Putting in (Eq. 1) and (Eq. 2) into (Eq. 4), we obtain

U = integral((kq/r)(rho 4πr^2 dr)) , which simplifies to U = integral(kq rho 4πr dr).

The constants are k, q, rho and 4π, so we take them away from the integral and we finally arrive to

U = kq rho 4π (((r^2)/2) - ((0^2)/2)) = kq rho 4π (r^2)/2.

Putting rho = 3q/(4πr^3), we finally obtain

U = k (3/2) (q^2)/r , but the equation should be U = k (3/5) (q^2)/r.

What am I doing wrong? 47.60.54.205 (talk) 02:03, 13 May 2022 (UTC)[reply]

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Please help me out with some physics stuff[edit]

Hi, I see you're good at physics. May I ask for your help on the Geiger-Marsden experiments article?

Talk:Geiger-Marsden experiments

I want to know if I got my maths right with this one. I haven't done physics since high school, I'm rather rusty. I would much appreciate an expert's help. Kurzon (talk) 19:41, 18 June 2023 (UTC)[reply]

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