Jump to content

1868 New Jersey gubernatorial election

From Wikipedia, the free encyclopedia

1868 New Jersey gubernatorial election

← 1865 November 3, 1868 1871 →
 
Nominee Theodore Fitz Randolph John Insley Blair
Party Democratic Republican
Popular vote 83,955 79,333
Percentage 51.42% 48.58%

County results
Randolph:      50–60%      60–70%
Blair:      50-60%      60–70%

Governor before election

Marcus Lawrence Ward
Republican

Elected Governor

Theodore Fitz Randolph
Democratic

The 1868 New Jersey gubernatorial election was held on November 3, 1868. Democratic nominee Theodore Fitz Randolph defeated Republican nominee John Insley Blair with 51.42% of the vote.

General election

[edit]

Candidates

[edit]

Results

[edit]
New Jersey gubernatorial election, 1868[1]
Party Candidate Votes % ±%
Democratic Theodore Fitz Randolph 83,955 51.42% Increase 2.49
Republican John Insley Blair 79,333 48.58% Decrease 2.49
Total votes 163,288
Democratic gain from Republican Swing

References

[edit]
  1. ^ Kalb, Deborah (December 24, 2015). Guide to U.S. Elections. CQ Press. ISBN 9781483380353. Retrieved January 25, 2016.