1876 Georgia gubernatorial election
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The 1876 Georgia gubernatorial election was held on 4 October 1876 in order to elect the Governor of Georgia. Democratic nominee and former member of the U.S. House of Representatives from Georgia's 2nd district Alfred H. Colquitt defeated Republican nominee and former Mayor of Atlanta Jonathan Norcross.[1]
General election[edit]
On election day, 4 October 1876, Democratic nominee Alfred H. Colquitt won the election by a margin of 77,854 votes against his opponent Republican nominee Jonathan Norcross, thereby holding Democratic control over the office of Governor. Colquitt was sworn in as the 49th Governor of Georgia on 12 January 1877.[2]
Results[edit]
| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Democratic | Alfred H. Colquitt | 111,297 | 76.89 | |
| Republican | Jonathan Norcross | 33,443 | 23.11 | |
| Total votes | 144,740 | 100.00 | ||
| Democratic hold | ||||
References[edit]
- ^ "Gov. Alfred Holt Colquitt". National Governors Association. Retrieved 3 January 2024.
- ^ "GA Governor". ourcampaigns.com. 30 August 2021. Retrieved 3 January 2024.
Categories:
- Georgia (U.S. state) gubernatorial elections
- 1876 United States gubernatorial elections
- 1876 Georgia (U.S. state) elections
- October 1876 events
- 1876 in Georgia (U.S. state)
- 1870s in Georgia (U.S. state)
- 1870s Georgia (U.S. state) elections
- 1876 elections
- 1876 elections in North America
- 1876 elections in the United States
- United States gubernatorial elections in the 1870s
- Government of Georgia (U.S. state)