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1958 Wimbledon Championships – Boys' singles

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Boys' singles
1958 Wimbledon Championships
Final
ChampionUnited States Butch Buchholz
Runner-upIndia Premjit Lall
Score6–1, 6–3
Events
Singles men women boys girls
Doubles men women mixed boys girls
← 1957 · Wimbledon Championships · 1959 →

Jimmy Tattersall was the defending champion, but lost to Premjit Lall in the semifinals.

Butch Buchholz defeated Lall in the final, 6–1, 6–3 to win the boys' singles tennis title at the 1958 Wimbledon Championships.[1]

Draw

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Key

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Finals

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Semifinals Final
          
United States Butch Buchholz 6 8 6
Brazil Ronnie Barnes 8 6 3
United States Butch Buchholz 6 6
India Premjit Lall 1 3
India Premjit Lall 6 6
United Kingdom Jimmy Tattersall 2 2

Top half

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First round Second round Quarterfinals Semifinals
United States Butch Buchholz 6 6
Finland Lassie Lincoln 4 1
United States E Buchholz 6 6
Denmark J Leschly 3 1
Lebanon Karim Fawaz 3 2
Denmark Jan Leschly 6 6
United States E Buchholz 6 8 6
Brazil R Barnes 8 6 3
Italy Guiliano Fanfani 0 1
Brazil Ronnie Barnes 6 6 Brazil R Barnes 6 6
Pakistan A Ahmad 0 0 Brazil R Barnes 7 14
Portugal A Abreu 6 3 6 Soviet Union A Potanin 5 12
Monaco C Coste 3 6 4 Portugal A Abreu 1 0
France Alain Bresson 3 6 Soviet Union A Potanin 6 6
Soviet Union Andrei Potanin 6 8

Bottom half

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First round Second round Quarterfinals Semifinals
Spain José Luis Arilla 6 6
Socialist Federal Republic of Yugoslavia Srdjan Jelić 0 0 Spain JL Arilla 3 7 6
Sweden Thomas Hallberg 6 6 Sweden T Hallberg 6 5 2
Switzerland Bernard Auberson 1 1 Spain JL Arilla 4 5
Norway TE Vold 1 3 India P Lall 6 7
Republic of Ireland Michael Hickey 6 6 Republic of Ireland M Hickey 0 1
India Premjit Lall 6 6
India P Lall 6 6
United Kingdom J Tattersall 2 2
Poland Piotr Jamroz 7 6
Netherlands Jan Beukers 5 3
Poland P Jamroz 6 2 4
United Kingdom J Tattersall 2 6 6
Austria Peter Pokorny 0 5
United Kingdom Jimmy Tattersall 6 7

References

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  1. ^ "Boys' Singles Finals 1947-2017". wimbledon.com. Wimbledon Championships. Retrieved 13 August 2017.
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