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1978 tennis event results
Helen Cawley and JoAnne Russell were the defending champions, but lost in the quarterfinals to Françoise Dürr and Virginia Wade.
Kerry Reid and Wendy Turnbull defeated Mima Jaušovec and Virginia Ruzici in the final, 4–6, 9–8(12–10), 6–3 to win the ladies' doubles tennis title at the 1978 Wimbledon Championships.[1]
Click on the seed number of a player to go to their draw section.
- ^ Barrett, John (2014). Wimbledon: The Official History (4th ed.). Vision Sports Publishing. ISBN 9-781909-534230.
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Grand Slam events | |
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Virginia Slims Circuit |
- Washington (S, D)
- Hollywood (S, D)
- Houston (S, D)
- Los Angeles (S, D)
- Chicago (S, D)
- Seattle (S, D)
- Detroit (S, D)
- Kansas (S, D)
- Dallas (S, D)
- Boston (S, D)
- Philadelphia (S, D)
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Colgate Series |
- Sydney 1 (S, D)
- Melbourne (S, D)
- Johannesburg (S, D)
- London (S, D)
- Sydney 2 (S, D)
- Hilton Head Island (S, D)
- Hamburg (S, D)
- Rome (S, D)
- Chichester (S, D)
- Eastbourne (S, D)
- Indianapolis (S, D)
- Toronto (S, D)
- Mahwah (S, D)
- Tokyo 1 (S)
- San Antonio (S, D)
- Montreal (S, D)
- Atlanta (S, D)
- Phoenix (S, D)
- Minneapolis (S, D)
- Brighton (S, D)
- Filderstadt (S, D)
- Buenos Aires (S, D)
- Oldsmar (S, D)
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Team events | |
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