2014 ATP Challenger China International – Nanchang – Doubles
Appearance
Nanchang – Doubles | |
---|---|
2014 ATP Challenger China International – Nanchang | |
Champion | Chen Ti Peng Hsien-yin |
Runner-up | Jordan Kerr Fabrice Martin |
Score | 6–2, 3–6, [12–10] |
This was the first edition of the tournament.
Chen Ti and Peng Hsien-yin won the title, defeating Jordan Kerr and Fabrice Martin in the final, 6–2, 3–6, [12–10].
Seeds
[edit]- Chen Ti / Peng Hsien-yin (champions)
- Jordan Kerr / Fabrice Martin (final)
- Lee Hsin-han / Zhang Ze (semifinals)
- Ryan Agar / Huang Liang-chi (first round)
Draw
[edit]Key
[edit]- Q = Qualifier
- WC = Wild card
- LL = Lucky loser
- Alt = Alternate
- SE = Special exempt
- PR = Protected ranking
- ITF = ITF entry
- JE = Junior exempt
- w/o = Walkover
- r = Retired
- d = Defaulted
- SR = Special ranking
Draw
[edit]First round | Quarterfinals | Semifinals | Final | ||||||||||||||||||||||||
1 | T Chen H-y Peng | 6 | 6 | ||||||||||||||||||||||||
WC | R Hua S Liu | 3 | 4 | 1 | T Chen H-y Peng | 77 | 6 | ||||||||||||||||||||
Y Bai D Wu | 6 | 6 | Y Bai D Wu | 62 | 4 | ||||||||||||||||||||||
Gong Peng-Xiang Gong Xiao | 2 | 2 | 1 | T Chen H-y Peng | 6 | 6 | |||||||||||||||||||||
3 | H-h Lee Z Zhang | 6 | 7 | 3 | H-h Lee Z Zhang | 4 | 3 | ||||||||||||||||||||
N Kadchapanan D Udomchoke | 3 | 5 | 3 | H-h Lee Z Zhang | 6 | 4 | [10 | ||||||||||||||||||||
S Balaji Shuichi Sekiguchi | 6 | 6 | S Balaji S Sekiguchi | 2 | 6 | [6] | |||||||||||||||||||||
WC | Chen Long Wu Hao | 3 | 2 | 1 | T Chen H-y Peng | 6 | 3 | [12] | |||||||||||||||||||
M Gong H Kondo | 65 | 77 | [10] | 2 | J Kerr F Martin | 2 | 6 | [10] | |||||||||||||||||||
N Meister J Nedunchezhiyan | 77 | 62 | [4] | M Gong H Kondo | 2 | 7 | [10] | ||||||||||||||||||||
H Chung J-s Nam | 3 | 77 | [10] | H Chung J-s Nam | 6 | 5 | [7] | ||||||||||||||||||||
4 | R Agar L-c Huang | 6 | 65 | [7] | M Gong H Kondo | 3 | 4 | ||||||||||||||||||||
WC | Y Ning A Wang | 3 | 2 | 2 | J Kerr F Martin | 6 | 6 | ||||||||||||||||||||
D Matsukevich V Rudnev | 6 | 6 | D Matsukevich V Rudnev | w/o | |||||||||||||||||||||||
T Matsui G Soeda | 65 | 6 | [6] | 2 | J Kerr F Martin | ||||||||||||||||||||||
2 | J Kerr F Martin | 77 | 3 | [10] |