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2020 Tata Open Maharashtra – Doubles

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Doubles
2020 Tata Open Maharashtra
Final
Champions
Runners-up
Score6–2, 3–6, [10–8]
Details
Draw16
Seeds4
Events
Singles Doubles
← 2019 · Maharashtra Open · 2022 →

Rohan Bopanna and Divij Sharan were the defending champions,[1] but chose not to participate together. Bopanna played alongside Arjun Kadhe but lost in the first round to Antoine Hoang and Benoît Paire. Sharan teamed up with Artem Sitak but lost in the first round to Matthew Ebden and Leander Paes.

André Göransson and Christopher Rungkat won the title, defeating Jonathan Erlich and Andrei Vasilevski in the final, 6–2, 3–6, [10–8].

Seeds

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Draw

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Key

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Draw

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First round Quarterfinals Semifinals Final
1 Netherlands R Haase
Sweden R Lindstedt
65 6 [10]
77 3 [8] 1 3 3
65 6 [8] Monaco R Arneodo
Germany A Begemann
6 6
Monaco R Arneodo
Germany A Begemann
77 4 [10] 4 61
4 6 4 [8] Sweden A Göransson
Indonesia C Rungkat
6 77
Sweden A Göransson
Indonesia C Rungkat
3 6 [10] Sweden A Göransson
Indonesia C Rungkat
6 6
France A Hoang
France B Paire
3 7 [10] 3 3
WC 6 5 [7] Sweden A Göransson
Indonesia C Rungkat
6 3 [10]
Italy P Lorenzi
Italy S Travaglia
6 6 3 2 6 [8]
3 4 7 1 [8]
6 3 [8] 3 Israel J Erlich
Belarus A Vasilevski
5 6 [10]
3 Israel J Erlich
Belarus A Vasilevski
4 6 [10] 3 Israel J Erlich
Belarus A Vasilevski
77 6
India P Raja
India R Ramanathan
78 6 63 4
Alt 66 3 India P Raja
India R Ramanathan
6 6
WC Australia M Ebden
India L Paes
6 77 WC 2 1
2 2 65

References

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  1. ^ "Indian Success: Sharan/Bopanna Claim Title On Team Debut In Pune". atptour.com. 5 January 2019. Retrieved 1 February 2020.
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