Talk:Attenuated total reflectance

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after reading this article I still don't know what kind of information can be obtained after performing ATR-IR. Can someone address this ? — Preceding unsigned comment added by Leungchuenyan (talkcontribs) 13:30, 12 April 2011 (UTC)[reply]

does anyone know how to put a titania coat onto an atr crystal?

Wikipedia is not a publisher of original thought[edit]

The Results and Conclusion sections have nothing to do with an encyclopedic article. bcartolo (talk) 22:11, 30 September 2009 (UTC)[reply]

I hate to agree, but if this is indeed unpublished information, it is WP:OR and thus cannot remain in Wikipedia. If this material is correct, it looks rather important. It should be moved to some other public forum where it can be accessible to researchers who need this information. David spector (talk) 18:30, 14 October 2009 (UTC)[reply]

Changes 07/03/07[edit]

Further reading section removed as it points to the same link as the sources section 128.101.169.207 16:00, 3 July 2007 (UTC)[reply]

An application section would benefit this page. I plan to rough one in for others to add to.--Jesse Greener (talk) 15:00, 13 June 2010 (UTC)[reply]

How does it actually produce a measurement?[edit]

Where is the output radiation measured and what feature of the sample does it report on? I just see light bouncing around and some energy disappearing into the sample due to the "tunneling" effect, but no actual information being collected. I'm also worried that the amount of energy that "tunnels" is unstable and unpredictable unless the gap is extremely tiny, but then what is added by having a gap? 84.227.237.33 (talk) 21:31, 2 April 2014 (UTC)[reply]

The irradiating light is not refelected exactly at the phase boundary to the sample. You might say that the wave overlaps a bit into the sample. Some part of the overlapping light wave is however absorbed in the sample. Hence, in the light you seea after the reflection, there is a spectrum imprinted. --Maxus96 (talk) 12:15, 22 October 2016 (UTC)[reply]

diamonds[edit]

but its much higher cost means it is less widely used.

Ah, what? The cost of a small diamond is totally negligible next to that of a modern spectrometer. I believe practically all standard commercial ATR cells use a diamond. --Maxus96 (talk) 12:15, 22 October 2016 (UTC)[reply]