Talk:Bessel filter

Electronics Mid‑importance

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omega0 is not the cut-off frequency! This got me totally confused while I was trying to implement one. omega0 is a frequency chosen to give you the cut-off frequency you desire, which isn't the same thing. I have added a link to the paper that told me this (although I forgot to log in when I did it. It is http://ece-www.colorado.edu/~ecen2260/slides/FilterSlides.pdf The next question, of course, is how do you calculate omega0? I'll do some more thinking. Tim Band 11:51, 3 December 2007 (UTC)[reply]

omega0 is the reciprocal delay. You could work out a formula for 3dB point relative to omega0, I'm sure (it will depend on the order). Dicklyon (talk) 06:24, 27 August 2009 (UTC)[reply]

Can anyone explain how to realise a Bessel filter? How do you practically connect your operational amplifier? I really like this Bessel approach instead of the fast filters that are available. —Preceding unsigned comment added by Knoppson (talk • contribs) 22:46, 13 February 2010 (UTC)[reply]

Divide it up into second order sections and connect them as biquads — Preceding unsigned comment added by 71.167.69.198 (talk) 01:36, 29 March 2016 (UTC)[reply]

External links modified[edit]

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Equation Error[edit]

Before I created my account, I tried to correct the gain equation in the Example section, but a bot reverted the change in short order. It looks like the equation in the original article was correct, but an editor (173.218.206.57) changed it on 18 July 2020. The coefficient for the omega squared term should be 45, not 15. The gain equation is easy to derive from the transfer function and has nothing to do with, as the editor suggests, substituting omega squared for s. Once the equation is corrected, then an omega value of 1.756 (or 1.75567) yields a gain of sqrt(0.5). — Preceding unsigned comment added by HenriJBass (talk • contribs) 13:07, 13 October 2020 (UTC) Update: I corrected the equation. — Preceding unsigned comment added by HenriJBass (talk • contribs) 17:26, 13 October 2020 (UTC)[reply]