Talk:Jackson's theorem (queueing theory)

Page contents not supported in other languages.
From Wikipedia, the free encyclopedia

civil engineering?[edit]

When I was studying Queuing Theory, almost 20 years ago, I remember my professor saying something about this theorem having a relationship to the flow of water through pipes. Does it have any roots in civil engineering or was that just an analogy for our tiny, student brains?

Also, I think Wolfram provides a good reference for a form a Jackson's Theorem which I think Wikipedia refers to as Jackson's Inequality (but I'm haven't taken the time to see what relationship exists, if any):
Weisstein, Eric W. "Jackson's Theorem." From MathWorld--A Wolfram Web Resource. http://mathworld.wolfram.com/JacksonsTheorem.html

It probably should be investigated.

Chip.R 17:24, 23 August 2007 (UTC)[reply]

Requested move[edit]

Jackson's theorem (queueing theory) → Jackson's theorem (per request at WP:RM). 199.125.109.99 (talk) 15:54, 16 February 2009 (UTC)[reply]

Support move. Kittybrewster 18:14, 16 February 2009 (UTC)[reply]
Oppose as Chip.R says, there is more than one Jackson's theorem around such as http://mathworld.wolfram.com/JacksonsTheorem.html --Rumping (talk) 15:10, 23 February 2009 (UTC)[reply]
Support move Jackson's theorem in queueing theory is more widely cited (624 vs. 158 citations on Google Scholar) and article on Dunham theorem has different name on Wikipedia. Gareth Jones (talk)
Most of the 624 do not seem to use the phrase "Jackson's theorem".[1] I see 388 examples using the phrase "Jackson's theorem" but not "networks", "queues" or "probabilities",[2] but only 149 without "polynomials".[3]--Rumping (talk) 18:55, 25 February 2009 (UTC)[reply]
Good point, in fact referring to the result with the phrase "Jackson network" ([4] 112 references on Google Scholar) seems much more common than "Jackson's theorem" ([5] 3 references on Google Scholar). Do you think it's a good idea to move the page to Jackson network instead? Gareth Jones (talk) 10:17, 5 March 2009 (UTC)[reply]