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Talk:Ziegler spectrum

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Are Ziegler spectra sober?

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The article currently says in the "Properties" section, that Ziegler spectra often fail to be , but it being unknown whether they all are sober. But being sober implies being . So those Ziegler spectra which are not can not be sober, answering the open problem. What are thr correct statements? (This was mentioned in the comments of https://mathoverflow.net/questions/320561/does-anyone-use-non-sober-topological-spaces). Columbus240 (talk) 04:50, 19 September 2022 (UTC)[reply]