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Tsankov Island

Coordinates: 65°03′58″S 64°08′38″W / 65.06611°S 64.14389°W / -65.06611; -64.14389
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Tsankov Island
Tsankov Island is located in Antarctica
Tsankov Island
Tsankov Island
Location of Tsankov Island
Tsankov Island is located in Antarctic Peninsula
Tsankov Island
Tsankov Island
Tsankov Island (Antarctic Peninsula)
Geography
LocationAntarctica
Coordinates65°03′58″S 64°08′38″W / 65.06611°S 64.14389°W / -65.06611; -64.14389
ArchipelagoWilhelm Archipelago
Area9.48 ha (23.4 acres)
Length625 m (2051 ft)
Width216 m (709 ft)
Administration
Administered under the Antarctic Treaty System
Demographics
Populationuninhabited

Tsankov Island (Bulgarian: Цанков остров, romanizedTsankov ostrov, IPA: [t͡sɐnˈkɔf ˈɔstrof]) is the mostly ice-covered island 625 m long in west-southwest to west-northeast direction and 216 m wide in the Dannebrog Islands group of Wilhelm Archipelago in the Antarctic Peninsula region. Its surface area is 9.48 ha.[1]

The feature is named after the dermatologist Nikolay Tsankov, participant in the 2010/11 and subsequent Bulgarian Antarctic campaigns.[1]

Location

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Tsankov Island is located at 65°03′58″S 64°08′38″W / 65.06611°S 64.14389°W / -65.06611; -64.14389, which is 293 m northwest of Stego Island, 175 m east of Bodloperka Island, 1.18 km southeast of Sprey Island and 1.25 km west-southwest of Taralezh Island. British mapping in 2001.

Maps

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See also

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Notes

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  1. ^ a b Tsankov Island. SCAR Composite Gazetteer of Antarctica

References

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This article includes information from the Antarctic Place-names Commission of Bulgaria which is used with permission.