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1792 United States presidential election in Delaware

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1792 United States presidential election in Delaware

← 1788–89 November 2 – December 5, 1792 1796 →
 
Nominee George Washington John Adams
Party Independent Federalist
Home state Virginia Massachusetts
Electoral vote 3 3
Percentage 100.00%

President before election

George Washington
Independent

Elected President

George Washington
Independent

The 1792 United States presidential election in Delaware took place between November 2 and December 5, 1792, as part of the 1792 United States presidential election. The state legislature chose three members of the Electoral College, each of whom, under the provisions of the Constitution prior to the passage of the Twelfth Amendment, cast two votes for President.

Delaware's three electors each cast one vote for the incumbent, George Washington, and one vote for John Adams, the incumbent Vice President.[1]

Results

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United States presidential election in Delaware, 1792
Party Candidate Votes Percentage Electoral votes
Independent George Washington (incumbent) 100.00% 3
Totals 100.00% 3

See also

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References

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  1. ^ 1792 Presidential Electoral Vote Count Dave Leip's Atlas of U.S. Presidential Elections.