User talk:Jmmartingarcia

Re: Rubik 4x4x4[edit]

Hi,

I think 24!/2 is the right factor (after fixing the corner cubelets), if all the centre cubelets are distinguishable. The number of distinguishable permutations given is 24!/(4!⁶), assuming centre cubelets of the same colour are indistinguishable, and the odd/even factor of 2 should be included in that 4!⁶. Κσυπ Cyp 21:22, 2 August 2008 (UTC)[reply]