1840 Kentucky gubernatorial election
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| Elections in Kentucky |
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 Government |
The 1840 Kentucky gubernatorial election was held on 3 August 1840 in order to elect the Governor of Kentucky. Whig nominee and former member of the U.S. House of Representatives from Kentucky's 5th district Robert P. Letcher defeated Democratic nominee and former member of the U.S. House of Representatives from Kentucky's 11th district Richard French.[1]
General election[edit]
On election day, 3 August 1840, Whig nominee Robert P. Letcher won the election by a margin of 15,711 votes against his opponent Democratic nominee Richard French, thereby retaining Whig control over the office of governor. Letcher was sworn in as the 15th governor of Kentucky on 25 August 1840.[2]
Results[edit]
| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Whig | Robert P. Letcher | 55,370 | 58.27 | |
| Democratic | Richard French | 39,659 | 41.73 | |
| Total votes | 95,029 | 100.00 | ||
| Whig hold | ||||
References[edit]
- ^ "Robert Perkins Letcher". National Governors Association. Retrieved 23 April 2024.
- ^ "KY Governor". ourcampaigns.com. 16 April 2005. Retrieved 23 April 2024.
Categories:
- 1840 Kentucky elections
- Kentucky gubernatorial elections
- 1840 United States gubernatorial elections
- August 1840 events
- 1840 in Kentucky
- 1840s in Kentucky
- 1840s Kentucky elections
- 1840 elections
- 1840 elections in North America
- 1840 elections in the United States
- United States gubernatorial elections in the 1840s
- Government of Kentucky