1793 New Jersey gubernatorial election
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The 1793 New Jersey gubernatorial election was held on 3 June 1793 in order to elect the Governor of New Jersey. Federalist candidate Richard Howell was elected by the New Jersey General Assembly against fellow Federalist candidate and incumbent United States Senator from New Jersey Frederick Frelinghuysen and candidate John Rutherford.[1]
General election
[edit]On election day, 3 June 1793, Federalist candidate Richard Howell was elected by the New Jersey General Assembly by a margin of 11 votes against his foremost opponent and fellow Federalist candidate Frederick Frelinghuysen, thereby retaining Federalist control over the office of Governor. Howell was sworn in as the 3rd Governor of New Jersey that same day.[2][3]
Results
[edit]| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Federalist | Richard Howell | 25 | 52.08% | |
| Federalist | Frederick Frelinghuysen | 14 | 29.17% | |
| John Rutherford | 9 | 18.75% | ||
| Total votes | 48 | 100.00% | ||
| Federalist hold | ||||
References
[edit]- ^ "Richard Howell". National Governors Association. Retrieved 30 June 2024.
- ^ "Minutes and proceedings of the Council and General Assembly of the state of New-Jersey, in joint-meeting, from August 30, 1776 to October 29, 1799". archive.org. 14 August 2009. Retrieved 30 June 2024.
- ^ "NJ Governor". ourcampaigns.com. 30 April 2024. Retrieved 30 June 2024.
Categories:
- 1793 in New Jersey
- New Jersey gubernatorial elections
- 1790s New Jersey elections
- 1793 elections
- 1793 elections in North America
- 1793 elections in the United States
- 1790s in New Jersey
- Indirect elections
- United States gubernatorial elections in the 1790s
- Government of New Jersey
- 1793 United States gubernatorial elections