1814 Ohio gubernatorial election
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Elections in Ohio |
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The 1814 Ohio gubernatorial election was held on 11 October 1814, in order to elect the Governor of Ohio. Democratic-Republican candidate and incumbent United States Senator Thomas Worthington defeated incumbent Democratic-Republican Acting Governor Othniel Looker and Democratic-Republican candidate William Craig.[1]
General election
[edit]On election day, 11 October 1814, Democratic-Republican candidate Thomas Worthington won the election by a margin of 11,408 votes against his foremost opponent incumbent Democratic-Republican Acting Governor Othniel Looker, thereby retaining Democratic-Republican control over the office of Governor. Worthington was sworn in as the 6th Governor of Ohio on 8 December 1814.[2]
Results
[edit]Party | Candidate | Votes | % | |
---|---|---|---|---|
Democratic-Republican | Thomas Worthington | 17,579 | 73.83% | |
Democratic-Republican | Othniel Looker (incumbent) | 6,171 | 25.92% | |
Democratic-Republican | William Craig | 59 | 0.25% | |
Total votes | 23,809 | 100.00% | ||
Democratic-Republican hold |
References
[edit]- ^ "Thomas Worthington". National Governors Association. Retrieved 29 April 2024.
- ^ "OH Governor". ourcampaigns.com. 3 June 2004. Retrieved 29 April 2024.
Categories:
- 1814 Ohio elections
- Ohio gubernatorial elections
- 1814 United States gubernatorial elections
- October 1814 events
- 1814 in Ohio
- 1810s in Ohio
- 1810s Ohio elections
- 1814 elections
- 1814 elections in North America
- 1814 elections in the United States
- United States gubernatorial elections in the 1810s
- Government of Ohio