1846 Ohio gubernatorial election
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Elections in Ohio |
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The 1846 Ohio gubernatorial election was held on 13 October 1846, in order to elect the Governor of Ohio. Whig nominee William Bebb defeated Democratic nominee David Tod and Liberty nominee Samuel Lewis.[1]
General election
[edit]On election day, 13 October 1846, Whig nominee William Bebb won the election by a margin of 2,385 votes against his foremost opponent Democratic nominee David Tod, thereby retaining Whig control over the office of Governor. Bebb was sworn in as the 19th Governor of Ohio on 12 December 1846.[2]
Results
[edit]Party | Candidate | Votes | % | |
---|---|---|---|---|
Whig | William Bebb | 118,869 | 48.28% | |
Democratic | David Tod | 116,484 | 47.31% | |
Liberty | Samuel Lewis | 10,797 | 4.39% | |
Scattering | 46 | 0.02% | ||
Total votes | 246,196 | 100.00% | ||
Whig hold |
References
[edit]- ^ "William Bebb". National Governors Association. Retrieved 10 May 2024.
- ^ "OH Governor". ourcampaigns.com. 16 February 2005. Retrieved 10 May 2024.
Categories:
- 1846 Ohio elections
- Ohio gubernatorial elections
- 1846 United States gubernatorial elections
- 1846 in Ohio
- October 1846 events
- 1840s in Ohio
- 1840s Ohio elections
- 1846 elections
- 1846 elections in North America
- 1846 elections in the United States
- United States gubernatorial elections in the 1840s
- Government of Ohio