From Wikipedia, the free encyclopedia
1990 United States House of Representatives elections in Tennessee|
|
|
|
|
Majority party
|
Minority party
|
Third party
|
|
|
|
|
|
| Party
|
Democratic
|
Republican
|
Independent
|
| Last election
|
6
|
3
|
0
|
| Seats won
|
6
|
3
|
0
|
| Seat change
|
|
|
|
| Popular vote
|
369,294
|
288,633
|
58,778
|
| Percentage
|
51.51%
|
40.26%
|
8.20%
|
| Swing
|
 8.39%
|
 2.19%
|
6.18%
|
|
 Results by party winners Results by district margin Democratic hold Republican hold
|
Republican
60–70%
80–90%
>90
|
Democratic
50–60%
60–70%
70–80%
>90%
| |
The 1990 congressional elections in Tennessee was held on November 6, 1990, to determine who will represent the state of Tennessee in the United States House of Representatives.
Following the 1990 elections, no seats changed hands, leaving the Tennessee delegation at a 6-3 Democratic majority.[1][2]
| United States House of Representatives elections in Tennessee, 1990[1]
|
| Party
|
Votes
|
Percentage
|
Seats
|
+/–
|
|
|
Democratic
|
369,294
|
51.51%
|
6
|
—
|
|
|
Republican
|
288,633
|
40.26%
|
3
|
—
|
|
|
Independents
|
58,778
|
8.20%
|
0
|
—
|
|
|
Write-ins
|
167
|
0.02%
|
0
|
—
|
| Totals
|
716,872
|
100.00%
|
9
|
—
|
| Popular vote |
|---|
|
|
|
| Democratic |
|
51.51% |
| Republican |
|
40.26% |
| Other |
|
8.22% |
|
| House seats |
|---|
|
|
|
| Democratic |
|
66.67% |
| Republican |
|
33.33% |
|
Government